15m^2+12m^2-375m=300

Solution for 15m^2+12m^2-375m=300 equation:

15m^2+12m^2-375m=300

We move all terms to the left:

15m^2+12m^2-375m-(300)=0

We add all the numbers together, and all the variables

27m^2-375m-300=0

a = 27; b = -375; c = -300;
Δ = b2-4ac
Δ = -3752-4·27·(-300)
Δ = 173025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{173025}=\sqrt{225*769}=\sqrt{225}*\sqrt{769}=15\sqrt{769}$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-375)-15\sqrt{769}}{2*27}=\frac{375-15\sqrt{769}}{54}
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-375)+15\sqrt{769}}{2*27}=\frac{375+15\sqrt{769}}{54}
$